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A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the
A fish swimming in a horizontal plane has velocity = (4.00 i + 1.00 j) m/s at a point in the ocean where the position relative to a certain rock is = (16.0 - 1.40 ) m. After the fish swims with constant acceleration for 19.0 s, its velocity is = (15.0 - 1.00 j) m/s. (a) What are the components of the acceleration of the fish? ax = ay * m/s * m/s (b) What is the direction of its acceleration with respect to unit vector ? counterclockwise from the +x-axis (c) If the fish maintains constant acceleration, where is it at t = 28.0 s? m y E In what direction is it moving? counterclockwise from the +x-axis
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