A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electric field of magnitude 85.0 N/C that is directed at 20 from the plane of the sheet (Figure 1). Figure 1 of 1 20 0.400 m * -0.600 m- Part A Find the magnitude of the electric flux through the sheet. Express your answer with the appropriate units. Value Submit Request Answer Provide Feedback ? Units You measure an electric field of 1.26106 N/C at a distance of 0.163 m from a point charge. There is no other source of electric field in the region other than this point charge. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electric flux through a sphere. Part A What is the electric flux through the surface of a sphere that has this charge at its center and that has radius 0.163 m ? = Submit Request Answer Part B What is the magnitude of the charge? q= Submit Request Answer Provide Feedback ? ? N-m/C It was shown in Example 21.11 (Section 21.5) in the textbook that the electric field due to an infinite line of charge is perpendicular to the line and has magnitude E=X/2er. Consider an imaginary cylinder with a radius of r = 0.155 m and a length of 1 = 0.410 m that has an infinite line of positive charge running along its axis. The charge per unit length on the line is = 5.60 C/m. Part A What is the electric flux through the cylinder due to this infinite line of charge? Express your answer in newton times meters squared per coulomb. = Submit Request Answer Part B ? N-m/C What is the flux through the cylinder if its radius is increased to r = 0.590 m? Express your answer in newton times meters squared per coulomb. = Submit Request Answer Part C ? N-m/C What is the flux through the cylinder if its length is increased to Z = 0.840 m? Express your answer in newton times meters squared per coulomb. ?