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A force F = (4.07xi + 2.91y j)N, where x and y are in metres, acts on an object as it moves in the
A force F = (4.07xi + 2.91y j)N, where x and y are in metres, acts on an object as it moves in the x direction from the origin to x = 5.18m. Calculate the work done on the object by the force. Submit Answer Tries 0/10 4a. When a 4.11kg mass is hung vertically on a certain light spring that obeys Hooke's law, the spring stretches 2.76cm. If the 4.11kg mass is removed how far will the spring stretch if a 1.33kg is hung on it instead? Submit Answer Tries 0/10 4b. How much work must an external agent do to stretch the spring 3.92cm from its unstretched position? Submit Answer Tries 0/10 If it takes 3.44] of work to stretch a Hooke's law spring 13.0cm from its unstressed length, determine the extra work required to stretch it an additional 10.0cm. Tries 0/10 Submit Answer 6a. A 215g block is pressed against a spring of force constant 1.26kN/m until the block compresses the spring 11.0cm. The spring rests at the bottom of a ramp inclined at 56.6 to the horizontal. Using energy considerations, determine how far up the incline the block moves before it stops if there is no friction between the block and the ramp. Submit Answer Tries 0/10 6b. How far up the incline does the block move before it stops if the coefficient of kinetic friction is 0.300? Tries 0/10 Submit Answer A constant torque of 23.8Nm is applied to a grindstone whose moment of inertia is 0.100kg.m. Using energy principles, calculate the angular speed (in revolutions per second) after the grindstone has made 11.0 revolutions. (Neglect friction.) Do not enter units.
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