A force F with a magnitude length of 10 Newtons is applied to the point P at an angle of TT FS F with the horizontal as shown below Fv p FH Using trigonometry determine the horizontal component FH and the vertical component FV of the force Note that the triangle shown is a right triangle OFH 5 3 Newtons and Fy 5 Newtons OFH 5 Newtons and Fy 5 3 Newtons FH 5 2 Newtons and Fy 5 2 Newtons FH 5 3 Newtons and Fy 5 2 Newtons FH 5 2 Newtons and Fy 5 3 Newtons