Question
A function f(x) is said to have a removable discontinuity at x = a if both of the following conditions hold: 1. f is
A function f(x) is said to have a removable discontinuity at x = a if both of the following conditions hold: 1. f is either not defined or not continuous at x = a. 2. f(a) could either be defined or redefined so that the new function is continuous at x = a. Show that x + 12x +39 if x-6 if x = -6 f(x) = 0 -X 12x33 if x > -6 has a removable discontinuity at x = -6 by (a) verifying (1) in the definition above, and then (b) verifying (2) in the definition above by determining a value of f(-6) that would make f continuous at x=-6. f(-6)= would make f continuous at a = -6. Now draw a graph of f(x). It's just a couple of parabolas!
Step by Step Solution
3.41 Rating (154 Votes )
There are 3 Steps involved in it
Step: 1
Answer Solution Graph fa2 12x 43 4 212129 276 to be contin...Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get StartedRecommended Textbook for
Calculus Early Transcendentals
Authors: James Stewart, Daniel K. Clegg, Saleem Watson, Lothar Redlin
9th Edition
1337613924, 978-1337613927
Students also viewed these Accounting questions
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
Question
Answered: 1 week ago
View Answer in SolutionInn App