A genetic experiment involving peas yielded one sample of offspring consisting of 429 green peas and 154

yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 24%

of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution.

Question content area bottom

Part 1 What are the null and alternative hypotheses?

A.

H0:p0.24

H1:p<0.24

B.

H0:p0.24

H1:p>0.24

C.

H0:p=0.24

H1:p>0.24

D.

H0:p=0.24

H1:p0.24

E.

H0:p0.24

H1:p=0.24

F.

H0:p=0.24

H1:p<0.24

Part 2

What is the test statistic? z=enter your response here (Round to two decimal places as needed.)

Part 3 What is the P-value?

P-value=enter your response here (Round to four decimal places as needed.)

Part 4

What is the conclusion about the null hypothesis?

A. Failtoreject the null hypothesis because the P-value is lessthanorequalto the significance level, .

B. Reject the null hypothesis because the P-value is lessthanorequalto the significance level, .

C. Reject the null hypothesis because the P-value is greaterthan the significance level, .

D. Failtoreject the null hypothesis because the P-value is greaterthan the significance level, .

Part 5What is the final conclusion?

A. There is sufficient evidence to support the claim that less than 24% of offspring peas will be yellow.

B. There is sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow.

C. There isnot sufficient evidence to support the claim that less than 24% of offspring peas will be yellow.

D. There isnot sufficient evidence to warrant rejection of the claim that 24% of offspring peas will be yellow.