(A) gives the greatest value for the torques with the largest lever arm FA 10. A light meter stick is pivoted at P as shown in the figure and initially held horizontally. Then the stick is released with two forces F1 - 96 N and F2 - 16 N applied at its ends as shown in the figure. F2 is applied 25 cm 75 cm vertically up and F, makes an angle of a = 30 with the horizontal as shown. Find the 30' a net torque applied on the stick about the pivot point P. Ignore the weight of the F1 = 96 meter stick. Take counterclockwise torque (out of the paper) as positive and clockwise torque (into the paper) as negative. T= TF+ F2 a. -32 N.m b. ON.m 96 XO . 25 sin ( 30) + 16 x 0. 75 C. -9 N.m d. +33 N.m CT = 24 N. m e. +24 N.m 90)