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A golf ball is hit upward, with an initial velocity of 55 meters per second, at an angle of 41 with respect to the horizontal.

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A golf ball is hit upward, with an initial velocity of 55 meters per second, at an angle of 41 with respect to the horizontal. The ball is hit from a height of 8 meters above the ground. The horizontal distance x from the starting point and the heighty above the ground of the ball 1' seconds after it is hit are given by the parametric equations below. x= (v0 cos 0)t y= 4.9t2+ (v0 sin 6)t+ h Here v0 is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) How long is the ball in the air before it first touches the ground? Do not round any intermediate computations. Round your answer to the nearest hundredth. [1 seconds (b) What is the horizontal distance the ball travels before it first touches the ground? Round your answer to the nearest whole number. [1 meters

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