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A - Horizontal C - vertical Separation (m) |Plate Area (m?) Capacitance (F) |Plate Charge (C) Voltage (V) 0.0100 0.000100 8.90E-14 1.33E-13 1.5 0.0100 0.000125

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A - Horizontal C - vertical Separation (m) |Plate Area (m?) Capacitance (F) |Plate Charge (C) Voltage (V) 0.0100 0.000100 8.90E-14 1.33E-13 1.5 0.0100 0.000125 1.11E-13 1.66E-13 1.5 0.0100 0.000153 1.36E-13 2.03E-13 1.5 .A 0.0100 0.000202 1.79E-13 2.69E-13 1.5 0.0100 0.000254 2.25E-13 3.37E-13 1.5 6 0.0100 0.000302 2.68E-13 4.01E-13 1.5 0.0100 0.000355 3.14E-13 4.71E-13 1.5 8 0.0100 0.000400 3.54E-13 5.31E-13 1.5 Capacitance and Area C = EA/d 4.00E-13 y = 9E-10x 3.50E-13 R2 = 1 . ......." 3.00E-13 2.50E-13 .....' Capacitance (F) 2.00E-13 1.50E-13 1.00E-13 5.00E-14 0.00E+00 0.0000000.0000500.0001000. 0001500.0002000.0002500.0003000.0003500.0004000.000450 Plate Area (m2)Lab Group Members: You will be using this phet simulation: https://phet.colorado.edu/en/simulations/capacitor-lab You can also download the simulation from Canvas. We will be working with the simulation on the "Introduction" tab. View 10' Plate Charges X Capacitance-meter Charge -meter Electric Field Lines Meters Capacitance Plate Charge Disconnect Battery Stored Energy Capacitance Plate Charge (top) Voltmeter Separation 0.89x10 F 0.13x10 -C Electric Field Detector 10.0 mm Reset All Plate Area X 100.0 mm 2 ?V 1.5v Voltmeter - OV -1.5 V Note that the simulation uses units of mm for distance and mm for area. You will need to convert to m and m.Experiment 1. Capacitance and Area C = % Set the battery voltage to 1.5 Volts. In this part the distance, d, between the plates is kept constant d =10.0 mm and the area of the plates is changed. You are to record the values for area (in m2) and the capacitance C (in F). Take at least eight values of A and C, and record in an EXCEL Data Table. (a) Use Excel to plot C (on the vertical axis) vs. A (horizontal axis). Use at least 8 data points. (b) Create a trendline and include this with your graph. Adjust the number of decimal places used in the trendline equation so you have numbers that go two past the decimal point, to the hundredths place. (c) Use the slope of the line and your rst answer in the preliminaries to nd your experimental value for so, Include the correct units. a. Calculate the percentage difference between your experimental value for a) and the theoretical value of a) = 8.85 x10'12 F/m. experimental a) = experimental - theoretical percent difference x 100% theoretical 2. Capacitance and distance C = % : In this part the area, A, of the plate is kept constant A: 100 mm2 and the distance d between the plates is changed. You are to record the values for distance (in m) and the capacitance C (in F). Take at least eight values of d and C and record in an EXCEL Data Table. (a) Use Excel to plot C (on the vertical axis) vs. 1 (horizontal axis). Use at least 8 data d points. (b) Create a trendline and include this with your graph. Adjust the number of decimal places used in the trendline equation so you have numbers that go two past the decimal point, to the hundredths place. (c) Use the slope of the line and your second answer in the preliminaries to nd your experimental value for an Include the correct units. (d) Calculate the percentage difference between your experimental value for so and the theoretical value of 51). Show your work: experimental an = percent difference = A - Horizontal C - vertical Separation (m) Capacitance (F) |Plate Area (m?) | Plate Charge (C) Voltage (V) 200.0000 1.77E-13 0.0001 2.66E-13 1.5 N 163.9344 1.46E-13 0.0001 2.19E-13 1.5 142.8571 1.27E-13 0.0001 1.91E-13 1.5 133.3333 1.18E-13 0.0001 1.77E-13 1.5 UT 125.0000 1.10E-13 0.0001 1.65E-13 1.5 112.3596 9.90E-14 0.0001 1.49E-13 1.5 105.2632 9.40E-14 0.0001 1.40E-13 1.5 100.0000 8.90E-14 0.0001 1.33E-13 1.5 2.20E-13 Capacitance and distance C = EA/d 2.00E-13 1.80E-13 1.60E-13 y = 9E-16x R2 = 1 1.40E-13 1.20E-13 1.00E-13 8.00E-14 6.00E-14 4.00E-14 2.00E-14 0.00E+00 0.0000 50.0000 100.0000 150.0000 200.0000 250.0000Capacitance and Charge & Voltage: Q = CV (a) Set the value of the capacitor to C = 0.89 >

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