Question
A hot water coil with an overall conductance U-500 W/m-C is designed to heat a flow of 1000L/s of air from 25C to 35C.
A hot water coil with an overall conductance U-500 W/m-C is designed to heat a flow of 1000L/s of air from 25C to 35C. The design water flow rate is 1.5 L/s, and the water enters at 60C. Use following air and water properties for the calculation: Air Water Properties Cp, kJ/kg-K p, kg/m 1.005 4.185 1.164 983.2 Determine the heat transfer rate and outlet water temperature. b) Calculate the heat transfer area for the design using the -NTU method. Use the following relationship for the e-NTU calculation: 1 - e-Ntu(1-C) = [1 -0.0411C*(1-e-0.414Ntu)] - C*e-Ntu(1-C) UA where C* = min and Ntu Cmax Cmin
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Fundamentals of Heat and Mass Transfer
Authors: Incropera, Dewitt, Bergman, Lavine
6th Edition
978-0470055540, 471457280, 470881453, 470055545, 978-0470881453, 978-0471457282
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