A house's exterior is being washed with the help of a water pump. Water enters the pump at a speed of 0.2 m/s at 20C and 1 atm, and exits at a height of 5 m with a speed of 50 m/s at 25C and 1 atm. Under steady-state conditions, assuming that the amount of heat given off by the pump to the environment is equal to 15% of the work done on the pump, calculate the work done on the pump (in kJ/kg). Note: For water; Cp=4.18kJ/kgK g=9.81m/s^2