Question
A. In C++ implement std::map without using STL B. Write a for loop that takes an input from the user to add up the numbers
A. In C++ implement std::map without using STL
B. Write a for loop that takes an input from the user to add up the numbers from 1 to the specified number. (Provide the script and the output)
Sol12:
A. Implementing std::map
without using the STL involves creating your own associative container that stores elements as key-value pairs. Here\'s an example implementation in C++:
#include
// for std::pair template class Map { private: struct Node { Key key; Value value; Node*
left; Node*
right;
Node(Key k, Value v) :
key(k),
value(v),
left(nullptr),
right(nullptr) {} }; Node* root; public:
Map() :
root(nullptr) {} void
insert(Key key, Value value) { Node** cur = &root; while (*cur != nullptr) { if (key key) { cur = &((*cur)->
left); } else { cur = &((*cur)->
right); } } *cur = new
Node(key, value); } Value& operator
[](Key key) { Node** cur = &root; while (*cur != nullptr) { if (key key) { cur = &((*cur)->
left); } else if (key > (*cur)->key) { cur = &((*cur)->
right); } else { return (*cur)->value; } } *cur = new
Node(key, Value()); return (*cur)->value; } bool
contains(Key key) { Node* cur = root; while (cur != nullptr) { if (key key) { cur = cur->
left; } else if (key > cur->key) { cur = cur->
right; } else { return true; } } return false; } };
This implementation uses a binary search tree to store the key-value pairs, with the keys determining the position of each element in the tree. The insert
method adds a new element to the tree, while the operator[]
method retrieves the value associated with a given key (and inserts a new element with a default-constructed value if the key doesn\'t already exist). The contains
method checks if a given key exists in the tree.
B. Here\'s an example C++ for loop that takes an input from the user and adds up the numbers from 1 to the specified number:
cCopy code#include
int
main() {
int n;
std::
cout
\"Enter a number: \";
std::
cin >> n;
int sum =
0;
for (
int i =
1; i =>
std::
cout
\"The sum of the numbers from 1 to \"
\" is \"
std::
endl;
return
0; }
This code prompts the user to enter a number, then uses a for loop to add up the numbers from 1 to that number. The resulting sum is printed to the console. Here\'s an example output for the input 5
:
Enter a number:
5 The
sum of the numbers
from
1 to
5
is
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