A ladder 25 feet long is leaning against the wall of a building. Initially, the foot of the ladder is 7 feet from the wall. The foot of the ladder begins to slide at a rate of 2 ft/sec, causing the top of the ladder to slide down the wall. The location of the foot of the ladder, its x coordinate, at time t seconds is given by x(t)=7+2t. wall 25 ft. ladder ground (a) Find the formula for the location of the top of the ladder, the y coordinate, as a function of time t. The formula for y(t)= \\ 25- - (7 + 2t) . (Put your cursor in the box, click and a palette will come up to help you enter your symbolic answer.) X (b) The domain of t values for y(t) ranges from 0 to 9 (c) Calculate the average velocity of the top of the ladder on each of these time intervals (correct to three decimal places): time interval ave velocity time interval ave velocity [0,2] [2,4] [6,8] [8,9] (d) Find a time interval [a,9] so that the average velocity of the top of the ladder on this time interval is -20 ft/seci.e. a= 12:29 PM