A lens in air has front surface power +6.00 D, back surface power 8.00 D, thickness 6.0 m rn and refractive index 1.6. If the object is 0.25 m in front of the lens, where is the image located? Answer is ()0.167 m in front of the back surface Please use these any of these formulas Refraction equations L=n Uan' HNn=F EL=F Effectivity/transfer L+ = L/(l (d)L] Back vertex power Fv' = F1 /[1 (t)F1] + F2