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a.) Letf:[[1,n]][[1,n]]such that there existsg:[[1,n]][[1,n]]satisfying thatfgis the identity. Prove thatfis onto. b.) Letf:[[1,n]][[1,n]]such that there existsg:[[1,n]][[1,n]]satisfying thatgfis the identity. Prove thatffis one-to-one. What can we
a.) Letf:[[1,n]][[1,n]]such that there existsg:[[1,n]][[1,n]]satisfying thatfgis the identity. Prove thatfis onto.
b.) Letf:[[1,n]][[1,n]]such that there existsg:[[1,n]][[1,n]]satisfying thatgfis the identity. Prove thatffis one-to-one.
What can we conclude from part a and b?
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