A line has a slope of :/5 and goes through the point (7, 6). What is the equation of this line? Answer. y FORMATTING: In Mobius, a is written sqrt(a).Let f be a function that is differentiable at a. Which of the following is/are correct statements of the definition of f (a), the derivative of f at a? f(ath) - f(a) lim h-+0 h f(z) - f(a) lim flat h) - f(h) h-0 h f(x) - f(a) lim f(x) - f(a) lim I- Q O f(ath) - f(a) hChoose all the statements below that are TRUE. If a function is not differentiable at a point , then it is definitely not continuous there. By definition, if lime->a f (x) exists, then f is differentiable at a and the limit is f (a). If a function is differentiable at a point r, then it must be continuous there. If a function is not continuous at a point c, then it is definitely not differentiable there. ) If a continuous function has a vertical tangent line at a point z in its domain, then it is not differentiable at that point. If a function is continuous at a point , then it must be differentiable there.We wish to compute the derivative of f (I) = I using the definition 31+4 f (z) = lim f(x th) - f(I) h-0 h Notice that this is an indeterminate of the form (a) Compute and simplify f(Ith)-f(I) so it takes the form h f(x + h) - f(I) A h (3(x + h) + 4) (31 + 4) where the expression for A may contain x and h. A (b) Using your answer from (a), compute f' (x) = lim f( = th) - f(I) h-+0 hMatch each function to its derivative. v f(I) = f (z) = 1 f (z) = - -v f(I) =e - v f(=) = In(x2) v f(I) = In(x) 1. f' (x ) = 1 2. f (I) = - 1 3. f'(x) = er 4. f' (z ) = = 5. f'(x) = 6. f'() = Consider the function I 2 - 3r + 3 Find the derivative of y with respect to r. dy Hint: simplify first.