A man has a daughter and a son. The son is two years older than the daughter. In three years the man will be six times as old as the daughter is now, and in ten years he will be thirteen years older than the combined ages of his children. What is the man's present age? Hint: The inverse of a three by three matrix can be found using Jamovi/R or by using the following formula: M = e h ei - fh -(bi - ch) bf - ce 1 -(di - fg) ai - cg -(af - cd) a(ei - fh) - b(di - fg) + c(dh - eg) dh - eg -(ah - bg) ae - bd