Question: A man ( mass = 7 6 k g ) is standing on a beam of length L = 5 m supported by two cables

A man (mass =76kg) is standing on a beam of length L=5m supported by two cables (one on the left, one on the right). The right-hand cable is offset from the end of the beam by a fraction a=0.19 of the beam length. The man is standing a distance x from the left-hand side of the beam. The beam's mass is 107 kg . The problem for the man is that the two cables are fairly weak and could easily snap. The maximum safe tension for the left beam is 0.9103N while the maximum safe tension for the right beam is 1.1103N. If x is too small or too large, one -ff the cables will likely fail. What is the range of motion of the man to safely walk along the beam (xmax-xmin)?
Your answer should be in m, but enter only the numerical part in the box.
A man ( mass = 7 6 k g ) is standing on a beam of

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