A market analyst wants to know if the new website he designed is showing increased page views per visit. A customer is randomly sent to one of two different websites, offering the same products, but with different designs. The accompanying table shows the data from 30 randomly chosen customers from each website. Test the null hypothesis that the mean number of page visits is the same for the two websites. (This is a two-sided test. ) Assume that the data come from a population that is Normally distributed. Complete parts a through f below. Click the icon to view the data table and summary statistics of website page views per visit. a) Find the value of the t-statistic for the difference in sample mean page visits, YA - YB, for the null hypothesis. t= 0.67 (Round to two decimal places as needed.) 2 NN b) Calculate the degrees of freedom from the formula df = df = 57.96 (Round to two decimal places as needed.) c) Calculate the degrees of freedom using the rule that of = min (n, - 1, n2 - 1). df= 29.00 (Round to two decimal places as needed.) d) Find the P-value using the degrees of freedom from part b. The P-value is 0.503 (Round to three decimal places as needed.) e) Find the P-value using the degrees of freedom from part c. The P-value is 0.506. (Round to three decimal places as needed.) f) What do you conclude at a = 0.10? Ho for both cases. There sufficient evidence to reject the claim that the mean number of page views is the same for both websites.\f- - YA = 8.07 YB = 7.17 2 2 SA = 21.24 S = 21.25 SA = 4.61 SB = 4.61 = - YA - YB = 0.90 SE YA - YB = 1.19