A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be 3c = $14.50 . Based on previous surveys, the restaurant informs the marketing manager that the stande deviation is o- = $3.50 . Lunch bills are Normally distributed. To address the CEO's conjecture, the marketing manager carried out a hypothesis test of H0 : M = 13.50 vs. Ha : u > 13.50. Using the test statistic (5c 13.50)/% , the P-value for the hypothesis test equals: n O 0.025. O 0.077