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A mass of 514 g stretches a spring by 9.9 cm. The damping constant is c = 0.42. External vibrations create a force of
A mass of 514 g stretches a spring by 9.9 cm. The damping constant is c = 0.42. External vibrations create a force of F(t)= 0.3 cos 3t Newtons, setting the spring in motion from its equilibrium position with zero velocity. What is the imaginary part v, of the complex root of the homogeneous equation? Use g = 9.8- -. Express your answer in two decimal places.
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