A metal bar is in the xy-plane with one end of the bar at the origin. A force F-(6.76 N)+(-3.10 N) is applied to the bar at the point-2.24 m, y = 3.55 m. Part A What is the position vector for the point where the force is applied? Enter the x and y components of the radius vector separated by a comma. Fr. Ty 2.24,3.55 m Submit Previous Answers Part B Correct What is the magnitude of the torque with respect to the origin produced by F? Express your answer with the appropriate units. 4.137 ? Nm Submit Previous Answers Bequest Answer *Incorrect; Try Again; 4 attempts remaining Part C What is the direction of the torque with respect to the origin produced by F? +-direction O+y-direction +2-direction O --direction O-y-direction -z-direction Submit Previous Answers Request Answer *Incorrect; Try Again; 5 attempts remaining Provide Feedback