A metronome uses an inverted pendulum rod to control tempo A weight can be slid up the pendulum rod to decrease tempo, or down the pendulum rod to increase tempo A second fixed weight is hidden inside the metronome at the base of the pendulum The longer the distance between the two weights, the slower the tempo This equation is used to calculate the frequency of the metronome pendulum f frequency (number of back and forth cycles in 1 second) measured in hertz g the acceleration due to gravity 9 8 m s 2 L length of the rod in this case, the length of the rod between the two weights measured in meters Part I Each time the metronome's pendulum completes one back and forth cycle, it produces two ticks or beats To calibrate the metronome for beats per minute (bpm), the manufacturer needs to know the length of the pendulum for various tempos Solvefor L (3 points) Part II If f 1 6 then there are 2 beats a second, or 192 beats per minute (bpm) What is the length of the rod between the two weights at that tempo Use your equation from Part I to solve for L (3 points)

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A metronome uses an inverted pendulum rod to control tempo. A weight can be slid up the pendulum rod to decrease tempo, or down the

A metronome uses an inverted pendulum rod to control tempo. A weight can be slid up the pendulum rod to decrease tempo, or down the pendulum rod to increase tempo. A second fixed weight is hidden inside the metronome at the base of the pendulum. The longer the distance between the two weights, the slower the tempo. This equation is used to calculate the frequency of the metronome pendulum:

f= frequency (number of back and forth cycles in 1 second) measured in hertz

g= the acceleration due to gravity; 9.8 m/s²

L = length of the rod in this case, the length of the rod between the two weights measured in meters

Part I:Each time the metronome's pendulum completes one back and forth cycle, it produces two ticks or beats. To calibrate the metronome for beats per minute (bpm), the manufacturer needs to know the length of the pendulum for various tempos. SolveforL.

(3 points)

Part II:Iff= 1.6 then there are 2 beats a second, or 192 beats per minute (bpm). What is the length of the rod between the two weights at that tempo? Use your equation from Part I to solve forL.(3 points)