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A new highway is to be constructed. Design A calls for a concrete pavement costing $90 per foot with a 20-year life; four paved ditches

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A new highway is to be constructed. Design A calls for a concrete pavement costing $90 per foot with a 20-year life; four paved ditches costing $3 per foot each, and three box culverts every mile, each costing $7,000 and having a 20-year life. Annual maintenance will cost $1,700 per mile; the culverts must be cleaned every five years at a cost of $350 each per mile. Design B calls for a bituminous pavement costing $45 per foot with a 10-year life; three sodded ditches costing $1.60 per foot each, and three pipe culverts every mile, each costing $2,100 and having a 10-year life. The replacement culverts will cost $2,400 each. Annual maintenance will cost $2,700 per mile; the culverts must be cleaned yearly at a cost of $230 each per mile, and the annual ditch maintenance will cost $1.50 per foot per ditch. Compare the two designs on the basis of equivalent worth per mile for a 20-year period. Find the most economical design on the basis of AW and PW if the MARR is 10% per year. - Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. The AW value for Design A is $ /mi. (Round to the nearest hundreds.) The PW value for Design A is $ imi. (Round to the nearest hundreds.) The AW value for Design B is $ imi. (Round to the nearest hundreds.) The PW value for Design B is $ /mi. (Round to the nearest hundreds.) The most economical design on the basis of AW and PW is PIF NON Discrete Compounding: 1 - 10% Single Payment Uniform Series Compound Compound Sinking Amount Present Amount Present Fund Factor Worth Factor Factor Worth Factor Factor To Find F To Find P To Find F To Find P To Find A Given P Given F Given A Given A Given F FIP FIA PIA AIF 1.1000 0.9091 1.0000 0.9091 1.0000 1.2100 0.8264 2.1000 1.7355 0.4762 1.3310 0.7513 3.3100 2.4869 0.3021 1.4641 0.6830 4.6410 3.1699 0.2155 1.6105 0.6209 6.1051 3.7908 0.1638 1.7716 0.5645 7.7156 4.3553 0.1296 1.9487 0.5132 9.4872 4.8684 0.1054 2.1436 0.4665 11.4359 5.3349 0.0874 2.3579 0.4241 13.5795 5.7590 0.0736 2.5937 0.3855 15.9374 6.1446 0.0627 2.8531 0.3505 18.5312 6.4951 0.0540 3.1384 0.3186 21.3843 6.8137 0.0468 3.4523 0.2897 24.5227 7.1034 0.0408 3.7975 0.2633 27.9750 7.3667 0.0357 4.1772 0.2394 31.7725 7.6061 0.0315 4.5950 0.2176 35.9497 7.8237 0.0278 5.0545 0.1978 40.5447 8.0216 0.0247 5.5599 0.1799 45.5992 8.2014 0.0219 6.1159 0.1635 51.1591 8.3649 0.0195 6.7275 0.1486 57 2750 8.5136 0.0175 Capital Recovery Factor To Find A Given P AIP 1.1000 0.5762 0.4021 0.3155 0.2638 0.2296 0.2054 0.1874 0.1736 0.1627 0.1540 0.1468 0.1408 0.1357 0.1315 0.1278 0.1247 0.1219 0.1195 0.1175 A new highway is to be constructed. Design A calls for a concrete pavement costing $90 per foot with a 20-year life; four paved ditches costing $3 per foot each, and three box culverts every mile, each costing $7,000 and having a 20-year life. Annual maintenance will cost $1,700 per mile; the culverts must be cleaned every five years at a cost of $350 each per mile. Design B calls for a bituminous pavement costing $45 per foot with a 10-year life; three sodded ditches costing $1.60 per foot each, and three pipe culverts every mile, each costing $2,100 and having a 10-year life. The replacement culverts will cost $2,400 each. Annual maintenance will cost $2,700 per mile; the culverts must be cleaned yearly at a cost of $230 each per mile, and the annual ditch maintenance will cost $1.50 per foot per ditch. Compare the two designs on the basis of equivalent worth per mile for a 20-year period. Find the most economical design on the basis of AW and PW if the MARR is 10% per year. - Click the icon to view the interest and annuity table for discrete compounding when the MARR is 10% per year. The AW value for Design A is $ /mi. (Round to the nearest hundreds.) The PW value for Design A is $ imi. (Round to the nearest hundreds.) The AW value for Design B is $ imi. (Round to the nearest hundreds.) The PW value for Design B is $ /mi. (Round to the nearest hundreds.) The most economical design on the basis of AW and PW is PIF NON Discrete Compounding: 1 - 10% Single Payment Uniform Series Compound Compound Sinking Amount Present Amount Present Fund Factor Worth Factor Factor Worth Factor Factor To Find F To Find P To Find F To Find P To Find A Given P Given F Given A Given A Given F FIP FIA PIA AIF 1.1000 0.9091 1.0000 0.9091 1.0000 1.2100 0.8264 2.1000 1.7355 0.4762 1.3310 0.7513 3.3100 2.4869 0.3021 1.4641 0.6830 4.6410 3.1699 0.2155 1.6105 0.6209 6.1051 3.7908 0.1638 1.7716 0.5645 7.7156 4.3553 0.1296 1.9487 0.5132 9.4872 4.8684 0.1054 2.1436 0.4665 11.4359 5.3349 0.0874 2.3579 0.4241 13.5795 5.7590 0.0736 2.5937 0.3855 15.9374 6.1446 0.0627 2.8531 0.3505 18.5312 6.4951 0.0540 3.1384 0.3186 21.3843 6.8137 0.0468 3.4523 0.2897 24.5227 7.1034 0.0408 3.7975 0.2633 27.9750 7.3667 0.0357 4.1772 0.2394 31.7725 7.6061 0.0315 4.5950 0.2176 35.9497 7.8237 0.0278 5.0545 0.1978 40.5447 8.0216 0.0247 5.5599 0.1799 45.5992 8.2014 0.0219 6.1159 0.1635 51.1591 8.3649 0.0195 6.7275 0.1486 57 2750 8.5136 0.0175 Capital Recovery Factor To Find A Given P AIP 1.1000 0.5762 0.4021 0.3155 0.2638 0.2296 0.2054 0.1874 0.1736 0.1627 0.1540 0.1468 0.1408 0.1357 0.1315 0.1278 0.1247 0.1219 0.1195 0.1175

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