A news organization wants to estimate the population proportion p of voters in a very large electorate who support candidate Smith in an upcoming election. For this purpose, the news organization conducts a survey of 900 randomly chosen voters and finds that 485 of the surveyed voters support candidate Smith. The following printout shows an analysis the news organization performs:

Test and Cl for One Proportion Test of p = 0.5 vs p > 0.5 Sample X N Sample p 95% CI Z-Value P-Value 1 485 900 0. 538889 (0.506322, 0.571456) 2.33 0 . 010 Using the normal approximation