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A normally distributed population has mean 57,800 and standard deviation 750. 1. Find the probability that a single randomly selected element X of the population
A normally distributed population has mean 57,800 and standard deviation 750. 1. Find the probability that a single randomly selected element X of the population is between 57,000 and 58,000. 0-4621 . Find the mean 7800 and standard deviation 75.0 of X for samples of size 100. . Find the probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000. 0.9962 Answer 1: 0.4621 Answer 2: 57800 Answer 3: 750 Answer 4: 0.9962 Borachio eats at the same fast food restaurant every day. Suppose the time X between the moment Borachio enters the restaurant and the moment he is served his food is normally distributed with mean 4.2 minutes and standard deviation 1.3 minutes. 1. Find the probability that when he enters the restaurant today it will be at least 5 minutes until he is served. = 0-2692 . Find the probability that average time until he is served in eight randomly selected visits to the restaurant will be at least 5 minutes. 0.04088 Answer 1: 0.2692 Answer 2: 0.04088 Question 2 1 pts A state insurance commission estimates that 13% of all motorists in its state are uninsured. Suppose this proportion is valid. Find the probability that in a random sample of 50 motorists, at least 5 will be uninsured. You may assume that the normal distribution applies. A normally distributed population has mean 57,800 and standard deviation 750. 1. Find the probability that a single randomly selected element X of the population is between 57,000 and 58,000. 0.4641 . Find the mean 27800 and standard deviation 79 of X for samples of size 100. . Find the probability that the mean of a sample of size 100 drawn from this population is between 57,000 and 58,000. | 0-9962 Answer 1: 0.4641 Answer 2: 57800 Answer 3: 12 Borachio eats at the same fast food restaurant every day. Suppose the time X between the moment Borachio enters the restaurant and the moment he is served his food is normally distributed with mean 4.2 minutes and standard deviation 1.3 minutes. 1. Find the probability that when he enters the restaurant today it will be at least 5 minutes until he is served. = 0-2676 . Find the probability that average time until he is served in eight randomly selected visits to the restaurant will be at least 5 minutes. 0.0409 Answer 1: 0.2676 Answer 2: 0.0409
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