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A notaw. indicator of a baby's health is the weight gained in the first year of the baby's life. Assume that the population of Espanol

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A notaw. indicator of a baby's health is the weight gained in the first year of the baby's life. Assume that the population of Espanol all such weight gains for baby boys is approximately normally distributed. A study claimed that the mean of this population is 8.921 k-As a practicing pediatrician, you want to test this claim. So, you select a random sample of 13 baby boys, and you record the weight each gained in their first year. Follow the steps below to construct a 90% confidence interval for the population mean of all the weight gains for baby boys in ? their first year. Then state whether the confidence interval you construct contradicts the study's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Number of baby Sample mean Sample standard boys deviation Take Sample 6.038 1.691 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 90% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". Sample size: Standard error Point estimate: Critical values Sample standard deviation: Margin of errors '0.005 3.055 0.010 2.681 Critical value: 90% confidence interval: 0.025 2:179 Fo.050 1-782 Compute 10. 100 1-356 (b) Based on your sample, graph the 90%% confidence interval for the population mean of all the weight gains for baby boys in their first year. . Enter the values for the lower and upper limits on the graph to show your confidence interval. For the point (#), enter the claim 8.921 from the study 90% confidence interval 0:000 2 000 $ 090 101000 (c) Does the 90% confidence interval you constructed contradict the claim made by the study? Choose the best answer from the choices below. No, the confidence interval does not contradict the claim. The mean of 8 921 kg from the

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