A nuclear submarine approaches the surface of the ocean at 27.5 km/h and at an angle of 15.5 with the surface. What are the components of its velocity? See the figure to the right. C 15.5 27.5 km/h First, setup a vector to represent the situation with the angle in standard position. The magnitude is 27.5 km/hr and the angle is 0 = 15.5 (Do not include the degree symbol in your answer.) The horizontal component is 26.5 km/hr. (Round to one decimal place as needed.) The vertical component is 7.4 km/hr. (Round to two decimal places as needed.) Add the given vectors by components. U=0.356, 0=176.3 V=0.584, 0 329.2 W 0.114, 0w 103.2 = The resultant magnitude is 0.204. (Round to three decimal places as needed. Round all intermediate values to five decimal places as needed.) The resultant direction is . (Type your answer in degrees. Use angle measures greater than or equal to 0 and less than 360. Round to the nearest integer as needed. Do not include the degree symbol in your answer.)