1. A nurse practitioner is completing his DNP project examining the impact of a new diabetes phone app to help decrease HgbA1C levels in his clinic's patient population. Six months after implementing the app he collects HgbA1C levels among his clinic patients and patients at another system clinic not using the phone app.

1. Identify the independent and dependent variables and level of measurement. (0.125 points each)

IV = Level of measurement:

DV = Level of measurement:

1. Describe which measure of central tendency and variability would be most appropriate to report for the HgbA1C variable (0.25 points).
2. The researcher runs an independent samples t-test to determine if the mean HgbA1C differs by clinic. Highlight (or circle) on the printout below all the values you would interpret. (0.25 points)
3. Interpret the output by writing up the findings as recommended by Kim, Mallory & Valerio and our instructional videos (1 point).

Group Statistics
	Facility	N	Mean	Std. Deviation	Std. Error Mean
HgbA1C	Non-Implementation	64	10.21	12.345	1.861
Implementation group	62	7.24	8.047	1.042

Independent Samples Test
	Levene's Test for Equality of Variances	t-test for Equality of Means
F	Sig.	t	df	Sig. (2-tailed)	Mean Difference	Std. Error Difference	95% Confidence Interval of the Difference
Lower	Upper
HgbA1C	Equal variances assumed	1.306	.023	2.341	124	.022	2.531	2.459	-2.336	7.398
Equal variances not assumed			1.037	104.092	.023	2.531	2.441	-2.309	7.371

1. A nurse manager is interested in determining if there is a relationship between comorbidities (diabetes, hypertension, cancer) and length of stay (LOS). The manager recodes LOS into two groups. Group 1 = LOS 10 days or less and Group 2 = LOS greater than 10 days..

1. Identify the independent and dependent variables and level of measurement. (0.125 points each)

IV = Level of measurement:

DV = Level of measurement:

1. Explain why the Chi-square statistic was chosen(0.25 points).
2. Identify on the printout below which values you would interpret. (0.25 points)
3. Interpret the output by writing up the findings as recommended by Kim, Mallory & Valerio and our instructional videos (1 point). There is no relationship between number of co-morbidities and LOS (p>.05).

CoMorb * LOS Group Crosstabulation
Count
	LOS group	Total
LOS <=10	LOS>10
CoMorb	Diabetes	34	13	47
Hypertension	40	7	47
Cancer	23	9	32
Total	97	29	126

Chi-Square Tests
	Value	df	Asymptotic Significance (2-sided)
Pearson Chi-Square	2.793a	2	.247
Likelihood Ratio	2.928	2	.231
Linear-by-Linear Association	.022	1	.883
N of Valid Cases	126
a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 7.37.

Symmetric Measures
	Value	Approximate Significance
Nominal by Nominal	Phi	.149	.247
Cramer's V	.149	.247
N of Valid Cases	126

1. A nurse researcher suspects that ICU Length of Stay (LOS) measured in days may be associated with HgbA1C levels. He runs an analysis to determine if this is true.

1. Write the null and alternative hypothesis. (0.25 points each)
2. Null =
3. Alternative =
   1. Identify on the printout which values you would interpret. (0.5 points)
   2. Interpret the output by writing up the findings as recommended by Kim, Mallory & Valerio and our instructional videos (1 point).

Correlations
	LOS	HgbA1C
LOS	Pearson Correlation	1	.316**
Sig. (2-tailed)		.000
N	126	126
HgbA1C	Pearson Correlation	.316**	1
Sig. (2-tailed)	.000
N	126	126
**. Correlation is significant at the 0.01 level (2-tailed).

1. An MSN student implemented a family navigation program for an outpatient surgery center. The Post Anesthesia Care Unit had been experiencing a large number of family inquiries because there was a lack of communication with patient families and what they should expect on the surgery day. The goal of the project was to improve family satisfaction (summative score of 10 questions rated on a scale of 0-10 for a total score between 0=100). The student collected data from patient families for 30-days pre-implementation and 30-days post-implementation of the navigation program.

1. Identify the independent and dependent variables and level of measurement. (0.125 points each)

IV = Level of measurement:

DV = Level of measurement:

1. Explain why the statistical analysis provided on the printout was chosen.(0.5 points)
2. Interpret the output by writing up the findings as recommended by Kim, Mallory & Valerio and our instructional videos. (1 point)

		Group Statistics
	Project	N	Mode	Median	Mean	Std. Deviation	Std. Error Mean
TotalScore	Pre-Implementation	1323	82	80	81.24	6.602	.907
Post-Implementation	1425	89	90	90.89	5.690	.889

Independent Samples Test
	Levene's Test for Equality of Variances	t-test for Equality of Means
F	Sig.	t	df	Sig. (2-tailed)	Mean Difference	Std. Error Difference	95% Confidence Interval
Lower	Upper
	TotalScore	Equal variances assumed	.733	.062	-2.795	2746	.017	-3.617	1.294	-6.187	-1.047
	Equal variances not assumed			-2.849	2743.23	.021	-3.617	1.270	-6.139	-1.095

1. Nursing administrators are examining the productivity of providers at a particular outpatient clinic. The administrators are concerned that some providers are seeing too many patients while others are seeing too few patients each day. However, they want to determine if this is an actual or perceived problem. They collect data on each of the three providers for 90 days to determine if there are differences.

1. Explain why the statistical analysis provided on the printout was chosen.(0.25 points).
2. Identify on the printout which values you would interpret. (0.25 points)
3. Interpret the output by writing up the findings as recommended by Kim, Mallory & Valerio and our instructional videos. (1.5 points).

Descriptives
Productivity
	N	Mean	Std. Deviation	Std. Error	95% Confidence Interval for Mean	Minimum	Maximum
Lower Bound	Upper Bound
Provider 1	90	31.24	3.503	.792	1.81	5.39	0	9
Provider 2	90	38.67	2.805	.496	8.55	10.57	5	16
Provider 3	90	33.76	2.363	.328	15.40	16.72	11	20
Total	270	34.56	4.985	.514	11.50	13.54	0	20

Test of Homogeneity of Variances
	Levene Statistic	df1	df2	Sig.
Productivity	Based on Mean	.342	2	267	.531

ANOVA
Productivity
	Sum of Squares	df	Mean Square	F	Sig.
Between Groups	235.356	2	52.323	51.343	.024
Within Groups	135.102	267	6.430
Total	370.458	269

Multiple Comparisons
Dependent Variable: Productivity
Scheffe
(I) Provider	(J) Provider	Mean Difference (I-J)	Std. Error	Sig.	95% Confidence Interval
Lower Bound	Upper Bound
1	2	-5.963*	.919	.023	-8.25	-3.68
3	-12.458*	.876	.067	-14.64	-10.28
2	1	5.963*	.919	.023	3.68	8.25
3	-6.495*	.570	.044	-7.91	-5.08
3	1	12.458*	.876	.067	10.28	14.64
2	6.495*	.570	.044	5.08	7.91
*. The mean difference is significant at the 0.05 level.