A one-way analysis of variance experiment produced the following ANOVA table Assume normality in the underlying populations (You may find it useful to reference the a table) SUMMARY Groups Column 1 Column 2 Column Count 6 6 6 Average 0.57 1.38 2.33 of Source of Variation Between Groups within Groups Total SS 9.12 5.33 14.46 MES 4.56 0.36 12.84 P-value 0.0006 15 17 Depicture Click here for the Excel Data File a. Conduct an ANOVA test at the 5% significance level to determine if some population means differ Reject Me, we can conclude that some population means differ. Reject He we cannot conclude that some population means differ, Do not reject He: we can conclude that some population means differ Do not reject Ho; we cannot conclude that some population means differ - b. Calculate 95% confidence interval estimates of 1 - , H4-43, and M2 Hy with Tukey's HSD approach. (If the exact value for me cis not found in the table, then round down. Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) Confidence Interval Population Mean Differences P12 P1P3 H2H c. Given your response to part b, which means significantly differ? Can we conclude that the population means differ? Population Mean Differences M1 M2 Hi-H3 H2 H3