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A parallel-plate capacitor C is charged up to a potential V 0 with a charge of magnitude Q 0 on each plate. It is then

A parallel-plate capacitor C is charged up to a potential V₀ with a charge of magnitude Q₀ on each plate. It is then disconnected from the battery, and the plates are pulled apart to fourfold their original separation.

part A- What is the new capacitance in terms of C?

part B- How much charge is now on the plates in terms of Q₀?

part C- What is the potential difference across the plates in terms of V₀?

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