A particle moves along a straight line and its position at time t is given by s(t) = 2t3 - 18t + 48t where s is measured in feet and t in seconds. Find the velocity (in ft/sec) of the particle at time t = 0: The particle stops moving (i.e. is in a rest) twice, first when t= and again when t What is the position of the particle at time 12? Finally, what is the TOTAL distance the particle travels between time 0 and time 12? Question Help: Video Submit Question