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A particle of mass 'm' is moving under an attractive delta potential V(x) = -V8 (x) [V > 0] and the particle is initially

A particle of mass 'm' is moving under an attractive delta potential V(x) = -V8 (x) [V > 0] and the particle is initially in the ground state of the potential. Now, if the strength of the potential 'V' is suddenly changed to '27', then the probability of the finding the particle in the ground state of the new potential, will be _(upto two decimal places)

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