A particular manufacturing design requires a shaft with a diameter of 22.000 mm, but shafts with diameters between 21.989 mm and 22.011 mm are acceptable. The manufacturing process yields shafts with diameters normally distributed, with a mean of 22.005 mm and a standard deviation of 0.005 mm. Complete parts (a) through (d) below. a. For this process, what is the proportion of shafts with a diameter between 21.989 mm and 22.000 mm? The proportion of shafts with diameter between 21.989 mm and 22.000 mm is 1 (Round to four decimal places as needed.) b. For this process, what is the probability that a shaft is acceptable? The probability that a shaft is acceptable is (Round to four decimal places as needed.) c. For this process, what is the diameter that will be exceeded by only 0.5% of the shafts? The diameter that will be exceeded by only 0.5% of the shafts is | mm. (Round to four decimal places as needed.) d. What would be your answers to parts (a) through (c) if the standard deviation of the shaft diameters were 0.004 mm? If the standard deviation is 0.004 mm, the proportion of shafts with diameter between 21.989 mm and 22.000 mm is (Round to four decimal places as needed.) If the standard deviation is 0.004 mm, the probability that a shaft is acceptable is (Round to four decimal places as needed.) If the standard deviation is 0.004 mm, the diameter that will be exceeded by only 0.5% of the shafts is mm. (Round to four decimal places as needed.)