Question: A particular solution of the equation y+ 4y' + 4y = 8 sin 2x is y = p cos 2x + q sin 2x, where

A particular solution of the equation y"+ 4y\' + 4y = 8 sin 2x is  y = p cos 2x + q sin 2x, where p and q are constants. 

(i) Find the values of p and q. 

(ii) Given that y(0) = 1 and y\' (0) = 0, find the solution of the differential equation.

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