A patient receives medicine through IV at a constant rate of 50 mg per hour. Once the medicine is in the patient's body it breaks down at a rate proportional to the amount currently present, with a constant of proportionality 0.002(hour) 1. Select the differential equation for Q(t), the amount of medicine in the patient's body at the time t ( in hours) o dQ 50 + 0.002t dt o dQ = 0.002 - 50t dt O dQ = 50 - 0.002Q dt O dQ = 0.002 - 50Q dt O dQ = 50 - 0.002t dt O dQ = 50 + 0.002Q dt