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A person standing on the edge of a high cliff throws a rock straight up with an initial velocity of 15.4 m/s. The rock

 

A person standing on the edge of a high cliff throws a rock straight up with an initial velocity of 15.4 m/s. The rock misses the edge of the cliff as it falls back to earth. Let y = 0, where y, is the vertical position of i the rock the moment it leaves the person's hand. Calculate the position of the rock 3.59 s after it is thrown. Maintain the same units. Normal format and 3 SF.

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