A piece of steel of unknown mass at a temperature of 98.2C is dropped into a beaker containing 780 g of water at a temperature 11.2C. Ignore heat loss to the surroundings and the beaker. If the final equilibrium temperature of the system is 56.7C, the mass (in kg) of the piece of steel is closest to: A) 1.94 B) 2.23 C) 1.76 D) 1.61 E) 1.80 MEAT = MCAT M (440)(87)= (0,78) (4180) (45,5 m = (0,78) (4180) (567) 38280 = 148348,2 (440) (2756,7) 249483=