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A point particle of mass m = 1.6 kg moves according to the position function: r (t) = xt a i + yt b j

A point particle of massm=1.6kg moves according to the position function:r(t) =xtai+ytbj+ztck, wheretdenotes time andx,y,z,a,b, andcare constants such that the exponents are positive integers and the position function has the dimension of length.

A We can write the particle's velocity function in the form v(t) = ntdi + otej + ptgk. Enter an expression for n in terms of x, y, z, a, b, and c.

B Here is a set of parameter values for the motion of the particle: m = 1.6 kg, x = 1.7 m/s3, y = 2.5 m/s3, z = 0.15 m/s1, a = 3, b = 3, c = 1. Calculate the x-component of the particle's angular momentum, in units of kgm2/s, about the origin at time t = 1 s.

C Use the same set of parameter values (m = 1.6 kg, x = 1.7 m/s3, y = 2.5 m/s3, z = 0.15 m/s1, a = 3, b = 3, c = 1) to calculate the y-component of the particle's angular momentum, in units of kgm2/s, about the origin at time t = 1 s.

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