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A poll of 10781078 Americans showed that 46.846.8% of the respondents prefer to watch the news rather than read or listen to it. Use those

A poll of 10781078 Americans showed that 46.846.8% of the respondents prefer to watch the news rather than read or listen to it. Use those results with a 0.010.01 significance level to test the claim that fewer than half of Americans prefer to watch the news rather than read or listen to it. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. Question content area bottom Part 1 Let p denote the population proportion of all Americans who prefer to watch the news rather than read or listen to it. Identify the null and alternative hypotheses. Upper H 0H0: p equals= 0.50.5 Upper H 1H1: p less than< 0.50.5 (Type integers or decimals. Do not round.) Part 2 Identify the test statistic. zequals=negative 2.102.10 (Round to two decimal places as needed.) Part 3 Identify the P-value. P-valueequals=0.0180.018 (Round to three decimal places as needed.) Part 4 State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that fewer than half of Americans prefer to watch the news rather than read or listen to it

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