A positive charge, Q = +3.0 nC is placed at y = +5.0 cm and a negative charge Q = -3.0 nC is placed at y = -5.0 cm as shown in the figure. A third positive charge, q = +0.01 nC is placed at the origin. +5 cm 0 -5 cm Q --- Q 8 7 2 3 5 9. The force is zero (a) What is the (i) direction of the net force acting on charge, q? Choose the direction from the arrows shown. Choose #9 if the net force is zero (which is NOT the correct answer here). Direction (ii) The magnitude of the net force on q is: Magnitude