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A possible solution to the differential equation t dy at + 2y = 4t + 1 would be: Oy = 4t + Oy = 3

A possible solution to the differential equation t dy at + 2y = 4t + 1 would be: Oy = 4t + Oy = 3 + Oy = 212 +t + t-1 Oy= 2+1+t

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