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A potato is launched vertically with an initial velocity of 125 ft /3 from the top of a 50-foot-tall building. After t seconds, its height

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A potato is launched vertically with an initial velocity of 125 ft /3 from the top of a 50-foot-tall building. After t seconds, its height above the ground is given by 3(t) = 16f2 + 1251: + 50. Round your answers to 2 decimal places. a. Find the velocity of the potato after 0.5 s and 6.75 s. After 0.5 seconds the velocity is 109 ft/s. o' 109 After 6.75 seconds the velocity is I -91 ' ft/s. o\" b. Find the speed of the potato after 0.5 S and 6.75 S. After 0.5 seconds the speed is 109 v" ft/s. o\" After 6.75 seconds the speed is ft/s. c. Find the acceleration of the potato after 0.5 s and 6.75 5. After 0.5 seconds the acceleration is ft / 32. After 6.75 seconds the acceleration is ft / 52. d. Determine how long the potato is in the air. The potato is in the air for seconds. e. Determine the velocity of the potato upon hitting the ground. The velocity as it hits the ground is ft/S

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