A projectile follows the trajectory 2 c(t)= l80t,50t4?8], where t is in seconds and distances are in meters. Here the a: and y coordinates represent the horizontal and vertical displacements. Then i) The projectile's height at t = 2 is (to the nearest meter) 80 o . ii) Its maximum height is (to the nearest meter) 128 o . iii) The slope of its trajectory at t = 2 is (as a fraction) - iv) The slope of its trajectory at t = 15 is (as a fraction)