A proton is placed in a uniform electric field of

$2600\frac{N}{C}.$

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Electron in a uniform field.

$F=(1\mathrm{.}60{10}^{-19}C)(2600\frac{N}{C})=4\mathrm{.}16{10}^{-16}N$

Part B

Calculate the proton's acceleration.

Express your answer in meters per second squared.

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Correct

$a=\frac{F}{m}=\frac{4\mathrm{.}16{10}^{-16}(N)}{1\mathrm{.}67{10}^{-27}(kg)}=2\mathrm{.}49{10}^{11}\frac{m}{s^2}$

Part C

Calculate the proton's speed after $1\mathrm{.}20s$ in the field, assuming it starts from rest.

Express your answer in meters per second.

$v=$

$\frac{m}{s}$