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A proton moves at 4.80 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.40
A proton moves at 4.80 x 105 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 9.40 x 10 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 5.50 cm horizontally. ns (b) Find its vertical displacement during the time interval in which it travels 5.50 cm horizontally. (Indicate direction with the sign of your answer.) 1.116 X Your response differs from the correct answer by more than 10%. Double check your calculations. mm (c) Find the horizontal and vertical components of its velocity after it has traveled 5.50 cm horizontally. 7 = + ) km/s
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a Horizontal travel time Given horizontal speedvx 480 x 105 ms Horizontal distancedx 550 cm 550 x 10...Get Instant Access to Expert-Tailored Solutions
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