A proton moves in the magnetic field B=0.501 T with a speed of 1.2x107 m/s in the directions shown in (Figure 1) and (Figure 2). What is the magnetic force on the proton in (Figure 1)? Enter components of the force in piconewtons separated by commas. View Available Hint(s) Fr. F. F. 0,6.78810-13,0 Submit Previous Answers * Incorrect; Try Again; 5 attempts remaining Figure 1 of 2 Part B 100 x PN What is the magnetic force on the proton in (Figure 2)? Enter components of the force in piconewtons separated by commas. View Available Hint(s) x vx x. x X X.10 A proton moves in the magnetic field B=0.50 T with a speed of 1.2x107 m/s in the directions shown in (Figure 1) and (Figure 2). * Incorrect; Try Again; 5 attempts remaining igure < 2 of 2 45 B x Part B What is the magnetic force on the proton in (Figure 2)? Enter components of the force in piconewtons separated by commas. View Available Hint(s) x b x vx x x X X.10 F. F. F6.788 10-13,0,0 Submit Previous Answers PN * Incorrect; Try Again; 4 attempts remaining Your answer implies that the vectors of the charged particle's velocity and the magnetic field strength are collinear, which is not the case according to the figure. Recall how a vector cross product is calculated and use the left-hand rule. You may need to review The Vector Cross Product. You may want to review Hint 3. Simplify: velocity.