Question
A proton moving with velocity 5.5x10 5 m/s, enters a region of space in which source charges have created an electric potential. a) What is
A proton moving with velocity 5.5x105 m/s, enters a region of space in which source charges have created an electric potential.
a) What is the proton's velocity after it moves through a potential difference of 100V?
b) By how much did the proton's electric potential energy change?
c) At some time later, the proton moves out of the region of space with the electric potential. It then comes to a stop 3 cm to the right of an electron.
i) Draw a picture of what is described above in part "c"
ii) What is the electric potential at point P which is 4 cm above the proton, due to the charge of the proton?
iii) What is the electric potential at point P due to the charge of the electron?
iv) What is the total electric potential at point P from the two charges?
Equation sheet for reference:
PHY162 Equation Sheet and Concepts for Exam 2, Ch 20-21 Electricity Constants Electron's Charge: e = 1.60 x 10-"9C Electron mass: 9.11x10-31kg Proton mass: 1.67x10-27kg k = 8.99 x 109 N Eo = 8.85 x 10-12 Cz Nm2 1 electron volt = 1 ev = 1.60x10-19/ Area of sphere: Anr2 Area of disk: nr2 Ch. 20 Electric Force: F = k 191/1921 F1 = F12 + F13 + F14 Electrick Field: E = E = Kq Ecapacitor = EOA Ch. 21 Work: W = -qEd AUF = -W Energy Conservation: KA + UA = KB = UB - -mvA + qVA = 5 mvp + qVB Electric Potential Energy: UE = qoV = k- Electric Potential: V = kq AV capacitor = Ed Capacitance: Q = CAV capacitor C = EDA d Concept List Ch 20 Ch 21 Electrostatics Work (done by electric force) Electric Charges Energy Conservation Conservation of Charge Electric Potential Energy Polarization Electric Potential (and how related to electric field) Charge Separation (of point charge and multiple charges) Coulomb's Law Potential Difference in parallel plate capacitors Electric Force Capacitance, Capacitors, and Energy Storage Electric Field (a point charge and multiple charges) DefibrillatorStep by Step Solution
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