A proton traveling at 3.50 km/s suddenly enters a uniform magnetic field of 0.760 T, traveling at an angle of 55 with the field lines (see (Figure 1)). Figure 55.0 B + Proton Part C Correct Correct answer is shown. Your answer 3.5-10-16 = 3.510-16 N was either rounded differently or used a different Important: If you use this answer in later parts, use the full unrounded value in your calculations. If you can vary the direction of the proton's velocity, find the magnitude of the maximum force you could achieve. Express your answer in newtons. ? xa Xb x x x X x X.10" Fmax = |1.2 10-15 You have already submitted this answer. Enter a new answer. No credit lost. Try again. Submit Previous Answers Request Answer Part D N If you can vary the direction of the proton's velocity, find the magnitude of the minimum force you could achieve. Express your answer in newtons. Fmin = 0 N Submit Previous Answers Correct