A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.32 hours, with a standard deviation of 2.38 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.22 hours, with a standard deviation of 1.85 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no children and adults with children left parenthesis mu 1 minus mu 2 right parenthesis. Question content area bottom Part 1 Let mu 1 represent the mean leisure hours of adults with no children under the age of 18 and mu 2 represent the mean leisure hours of adults with children under the age of 18. The 90% confidence interval for left parenthesis mu 1 minus mu 2 right parenthesis is the range from enter your response here hours to enter your response here hours. (Round to two decimal places as needed.) Part 2 What is the interpretation of this confidence interval? A. There is 90% confidence that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours. B. There is a 90% probability that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours. C. There is 90% confidence that the difference of the means is in the interval. Conclude that there is insufficient evidence of a significant difference in the number of leisure hours. D. There is a 90% probability that the difference of the means is in the interval. Conclude that there is a significant difference in the number of leisure hours.